Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 22:04Z
4α² + 7α + 5 = 0
det| 7 4 ; 4 8 | = 40
66K
∑_{k=1}^{n} k = n(n+1)/2
222K
CH₄ + 2O₂ → CO₂ + 2H₂O
5θ² + 1θ + 7 = 0
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
392K
∑_{k=1}^{n} k = n(n+1)/2
32K