Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 21:31Z
10t² + 3t + 6 = 0
∫₀^∞ e^(-x²) dx = √π / 2
66K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\lim_{r\to 0} \frac{\sin r}{r} = 1
87K
8ψ² + 2ψ + 2 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
61K
∂β/∂y = 8β
\frac{7}{1} \sum_{i=1}^{n} i^{2}
119K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
472K