Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 15:44Z
E = mc²
det| 2 5 ; 6 3 | = -24
λ = h/p
∫₀^∞ e^(-t²) dt = √π / 2
29K
\lim_{y\to 0} \frac{\sin y}{y} = 1
CH₄ + 2O₂ → CO₂ + 2H₂O
211K
8r² + 3r + 5 = 0
det| 5 6 ; 2 6 | = 18
390K
det| 9 4 ; 1 10 | = 86
69K
2γ² + 9γ + 0 = 0
∇ × E = −∂B/∂t
d/dr [r^2] = 2r^1