Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:59Z
E = mc²
2ω² + 4ω + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
438K
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 7 1 ; 7 8 | = 49
211K
det| 2 1 ; 2 3 | = 4
det| 9 4 ; 1 10 | = 86
69K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\oint_C \vec{F}\cdot d\vec{r} = 0
352K
2H₂ + O₂ → 2H₂O