Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 23:49Z
3θ² + 8θ + 7 = 0
\frac{11}{6} \sum_{i=1}^{n} i^{2}
222K
∇ × E = −∂B/∂t
\lim_{t\to 0} \frac{\sin t}{t} = 1
2K
\frac{12}{3} \sum_{i=1}^{n} i^{2}
λ = h/p
det| 7 4 ; 4 8 | = 40
335K
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2
119K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
d/dβ [β^11] = 11β^10