Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:39Z
E = mc²
2ω² + 4ω + 5 = 0
det| 1 1 ; 5 2 | = -3
438K
E = mc²
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 2 1 ; 2 3 | = 4
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
144K
2H₂ + O₂ → 2H₂O