Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:08Z
E = mc²
2ω² + 4ω + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
90K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 2 1 ; 2 3 | = 4
det| 11 4 ; 5 12 | = 112
69K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{z\to 0} \frac{\sin z}{z} = 1
144K