Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:52Z
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
320K
det| 7 4 ; 4 8 | = 40
144K
2ω² + 4ω + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
90K
\frac{2}{2} \sum_{i=1}^{n} i^{2}
438K
E = mc²
\lim_{t\to 0} \frac{\sin t}{t} = 1
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 2 4 ; 4 3 | = -10
390K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
69K