Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 23:26Z
3θ² + 8θ + 7 = 0
∇ × E = −∂B/∂t
\binom{n}{k} = \frac{n!}{k!(n-k)!}
2K
\frac{12}{3} \sum_{i=1}^{n} i^{2}
\lim_{z\to 0} \frac{\sin z}{z} = 1
61K
λ = h/p
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
335K
iħ ∂ψ/∂t = Ĥψ
det| 9 4 ; 1 10 | = 86
472K
d/dβ [β^11] = 11β^10
\binom{n}{k} = \frac{n!}{k!(n-k)!}