Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 19:13Z
6α² + 1α + 3 = 0
∇²t = 0
10γ² + 9γ + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
394K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
211K
λ = h/p
det| 9 7 ; 3 10 | = 69
69K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{z\to 0} \frac{\sin z}{z} = 1