Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-20 00:42Z
∇²β = 0
∑_{k=1}^{n} k = n(n+1)/2
164K
3y² + 5y + 2 = 0
d/dx [x^2] = 2x^1
∑_{k=1}^{n} k = n(n+1)/2
165K
1φ² + 5φ + 7 = 0
e^{i\pi} + 1 = 0
3y² + 6y + 5 = 0
7n² + 3n + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∂x/∂x = 8x