Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:03Z
E = mc²
\frac{12}{6} \sum_{i=1}^{n} i^{2}
320K
2ω² + 4ω + 5 = 0
det| 7 1 ; 7 8 | = 49
90K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
438K
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
\frac{8}{7} \sum_{i=1}^{n} i^{2}
69K