Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:29Z
E = mc²
2ω² + 4ω + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
438K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
394K
det| 12 1 ; 4 13 | = 152
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 2 1 ; 2 3 | = 4
det| 7 4 ; 4 8 | = 40
390K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\frac{2}{2} \sum_{i=1}^{n} i^{2}
144K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
352K