Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:58Z
E = mc²
∫₀^∞ e^(-x²) dx = √π / 2
320K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
144K
2ω² + 4ω + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
90K
E = mc²
d/dz [z^11] = 11z^10
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
\frac{12}{7} \sum_{i=1}^{n} i^{2}
211K
\frac{8}{6} \sum_{i=1}^{n} i^{2}
390K
\frac{7}{1} \sum_{i=1}^{n} i^{2}
352K