Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:33Z
E = mc²
2ω² + 4ω + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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E = mc²
∑_{k=1}^{n} k = n(n+1)/2
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CH₄ + 2O₂ → CO₂ + 2H₂O
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\frac{9}{8} \sum_{i=1}^{n} i^{2}
\frac{11}{6} \sum_{i=1}^{n} i^{2}
94K
det| 2 1 ; 2 3 | = 4
det| 7 4 ; 4 8 | = 40
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
352K