Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:04Z
E = mc²
det| 7 4 ; 4 8 | = 40
320K
2ω² + 4ω + 5 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
394K
CH₄ + 2O₂ → CO₂ + 2H₂O
29K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
94K
∑_{k=1}^{n} k = n(n+1)/2
211K