Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:43Z
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
144K
2ω² + 4ω + 5 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
438K
E = mc²
det| 7 1 ; 7 8 | = 49
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 7 4 ; 4 8 | = 40
144K