Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 19:33Z
6α² + 1α + 3 = 0
\lim_{r\to 0} \frac{\sin r}{r} = 1
144K
∇²t = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
438K
10γ² + 9γ + 5 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
∑_{k=1}^{n} k = n(n+1)/2
94K
λ = h/p
det| 12 3 ; 4 13 | = 144
390K
F = ma
\binom{n}{k} = \frac{n!}{k!(n-k)!}
144K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{z\to 0} \frac{\sin z}{z} = 1