Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 22:56Z
4α² + 7α + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
66K
CH₄ + 2O₂ → CO₂ + 2H₂O
∫₀^∞ e^(-x²) dx = √π / 2
87K
5θ² + 1θ + 7 = 0
det| 4 6 ; 0 5 | = 20
61K
λ = h/p
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
380K
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
472K
ΔS ≥ 0
N₂ + 3H₂ ⇌ 2NH₃