Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:22Z
E = mc²
2ω² + 4ω + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
90K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
394K
det| 4 6 ; 4 5 | = -4
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
\frac{11}{6} \sum_{i=1}^{n} i^{2}
94K
det| 9 4 ; 1 10 | = 86
211K
det| 2 1 ; 2 3 | = 4
\binom{n}{k} = \frac{n!}{k!(n-k)!}