Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 23:00Z
3θ² + 8θ + 7 = 0
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
2K
\frac{12}{3} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
174K
\frac{2}{2} \sum_{i=1}^{n} i^{2}
61K
λ = h/p
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
380K
∑_{k=1}^{n} k = n(n+1)/2
335K
iħ ∂ψ/∂t = Ĥψ
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
d/dβ [β^11] = 11β^10