Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 02:07Z
1ψ² + 1ψ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
66K
d/dω [ω^8] = 8ω^7
det| 7 4 ; 4 8 | = 40
87K
∑_{k=1}^{n} k = n(n+1)/2
2K
11γ² + 5γ + 0 = 0
det| 5 6 ; 2 6 | = 18
61K
iħ ∂ψ/∂t = Ĥψ
det| 4 8 ; 3 5 | = -4
119K