Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:06Z
E = mc²
2ω² + 4ω + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
438K
E = mc²
\frac{9}{8} \sum_{i=1}^{n} i^{2}
\lim_{x\to 0} \frac{\sin x}{x} = 1
94K
det| 2 1 ; 2 3 | = 4
det| 9 4 ; 1 10 | = 86
69K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
2H₂ + O₂ → 2H₂O