Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:36Z
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
320K
d/dz [z^11] = 11z^10
144K
2ω² + 4ω + 5 = 0
det| 7 6 ; 1 8 | = 50
90K
det| 11 4 ; 5 12 | = 112
438K
E = mc²
det| 5 6 ; 1 6 | = 24
394K
det| 9 4 ; 1 10 | = 86
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 7 1 ; 7 8 | = 49
94K
CH₄ + 2O₂ → CO₂ + 2H₂O
69K