Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 23:55Z
3θ² + 8θ + 7 = 0
∇ × E = −∂B/∂t
∫₀^∞ e^(-β²) dβ = √π / 2
2K
\frac{12}{3} \sum_{i=1}^{n} i^{2}
λ = h/p
det| 7 4 ; 4 8 | = 40
335K
iħ ∂ψ/∂t = Ĥψ
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
d/dβ [β^11] = 11β^10