Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:57Z
E = mc²
\lim_{x\to 0} \frac{\sin x}{x} = 1
320K
2ω² + 4ω + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
90K
E = mc²
det| 2 7 ; 7 3 | = -43
394K
det| 2 4 ; 4 3 | = -10
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
94K
det| 7 4 ; 4 8 | = 40
211K
det| 2 1 ; 2 3 | = 4
\lim_{z\to 0} \frac{\sin z}{z} = 1
69K