Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:03Z
E = mc²
det| 1 4 ; 2 2 | = -6
320K
det| 4 6 ; 0 5 | = 20
144K
2ω² + 4ω + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
E = mc²
\frac{9}{8} \sum_{i=1}^{n} i^{2}
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
94K
det| 7 3 ; 6 8 | = 38
211K
det| 2 1 ; 2 3 | = 4
det| 9 4 ; 1 10 | = 86
390K
det| 12 3 ; 4 13 | = 144
69K
det| 5 6 ; 7 6 | = -12
144K