Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:22Z
E = mc²
det| 4 8 ; 3 5 | = -4
144K
2ω² + 4ω + 5 = 0
E = mc²
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 7 4 ; 4 8 | = 40
211K
det| 2 1 ; 2 3 | = 4
det| 12 3 ; 4 13 | = 144
390K
\lim_{z\to 0} \frac{\sin z}{z} = 1
69K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
144K
2H₂ + O₂ → 2H₂O
F = G m₁m₂ / r²