Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:49Z
E = mc²
2ω² + 4ω + 5 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
94K
det| 2 1 ; 2 3 | = 4
det| 7 4 ; 4 8 | = 40
390K
det| 12 3 ; 4 13 | = 144
69K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
d/dz [z^11] = 11z^10
144K
2H₂ + O₂ → 2H₂O