Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:36Z
E = mc²
2ω² + 4ω + 5 = 0
E = mc²
\lim_{z\to 0} \frac{\sin z}{z} = 1
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
\lim_{β\to 0} \frac{\sin β}{β} = 1
94K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
211K
det| 2 1 ; 2 3 | = 4
det| 9 2 ; 3 10 | = 84
390K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 11 2 ; 5 12 | = 122
2H₂ + O₂ → 2H₂O
F = G m₁m₂ / r²