Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:07Z
E = mc²
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
320K
2ω² + 4ω + 5 = 0
E = mc²
\lim_{z\to 0} \frac{\sin z}{z} = 1
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-t²) dt = √π / 2
94K
det| 5 6 ; 7 6 | = -12
211K
det| 2 1 ; 2 3 | = 4
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}