Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:11Z
E = mc²
∫₀^∞ e^(-t²) dt = √π / 2
144K
2ω² + 4ω + 5 = 0
E = mc²
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 2 1 ; 2 3 | = 4
CH₄ + 2O₂ → CO₂ + 2H₂O
144K