Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 16:14Z
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
144K
det| 8 9 ; 3 9 | = 45
E = mc²
det| 1 2 ; 4 2 | = -6
394K
det| 10 1 ; 6 11 | = 104
det| 10 2 ; 3 11 | = 104
94K
∑_{k=1}^{n} k = n(n+1)/2
390K
∑_{k=1}^{n} k = n(n+1)/2
69K
d/dz [z^11] = 11z^10
352K