Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:02Z
E = mc²
2ω² + 4ω + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
90K
E = mc²
det| 9 4 ; 1 10 | = 86
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
94K
det| 7 9 ; 1 8 | = 47
211K
∑_{k=1}^{n} k = n(n+1)/2
390K