Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 02:49Z
ΔS ≥ 0
\frac{1}{2} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
9θ² + 4θ + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
94K
det| 7 4 ; 4 8 | = 40
211K
det| 6 4 ; 1 7 | = 38
12ω² + 4ω + 5 = 0
det| 6 6 ; 7 7 | = 0