Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:39Z
E = mc²
2ω² + 4ω + 5 = 0
\lim_{x\to 0} \frac{\sin x}{x} = 1
90K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-x²) dx = √π / 2
94K
det| 2 1 ; 2 3 | = 4
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
144K
\lim_{t\to 0} \frac{\sin t}{t} = 1
352K