Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:35Z
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
320K
2ω² + 4ω + 5 = 0
\frac{11}{6} \sum_{i=1}^{n} i^{2}
90K
E = mc²
det| 10 7 ; 3 11 | = 89
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 7 4 ; 4 8 | = 40
211K
det| 2 1 ; 2 3 | = 4
det| 9 5 ; 6 10 | = 60
390K
\frac{2}{2} \sum_{i=1}^{n} i^{2}
69K
\binom{n}{k} = \frac{n!}{k!(n-k)!}