Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:07Z
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
144K
2ω² + 4ω + 5 = 0
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 2 1 ; 2 3 | = 4
det| 12 1 ; 5 13 | = 151
390K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 11 2 ; 5 12 | = 122
2H₂ + O₂ → 2H₂O