Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 15:43Z
E = mc²
det| 2 5 ; 6 3 | = -24
λ = h/p
\lim_{y\to 0} \frac{\sin y}{y} = 1
det| 9 4 ; 1 10 | = 86
94K
8r² + 3r + 5 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
390K
2γ² + 9γ + 0 = 0
12α² + 4α + 7 = 0
∇ × E = −∂B/∂t
d/dr [r^2] = 2r^1