Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 23:23Z
3θ² + 8θ + 7 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∇ × E = −∂B/∂t
\frac{4}{6} \sum_{i=1}^{n} i^{2}
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\frac{12}{3} \sum_{i=1}^{n} i^{2}
\lim_{z\to 0} \frac{\sin z}{z} = 1
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λ = h/p
iħ ∂ψ/∂t = Ĥψ
det| 7 4 ; 4 8 | = 40
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det| 7 1 ; 7 8 | = 49
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d/dβ [β^11] = 11β^10
det| 4 6 ; 0 5 | = 20
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
32K