Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 22:06Z
4α² + 7α + 5 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
5θ² + 1θ + 7 = 0
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
380K
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
119K
det| 7 8 ; 6 8 | = 8
472K
ΔS ≥ 0
N₂ + 3H₂ ⇌ 2NH₃