Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 23:05Z
3θ² + 8θ + 7 = 0
∇ × E = −∂B/∂t
\frac{6}{7} \sum_{i=1}^{n} i^{2}
2K
\frac{12}{3} \sum_{i=1}^{n} i^{2}
det| 7 4 ; 4 8 | = 40
174K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
61K
λ = h/p
\binom{n}{k} = \frac{n!}{k!(n-k)!}
380K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
472K
∑_{k=1}^{n} k = n(n+1)/2
392K