Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 02:00Z
1ψ² + 1ψ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
66K
d/dω [ω^8] = 8ω^7
∑_{k=1}^{n} k = n(n+1)/2
2K
11γ² + 5γ + 0 = 0
det| 7 4 ; 4 8 | = 40
174K
iħ ∂ψ/∂t = Ĥψ
det| 7 7 ; 4 8 | = 28
119K