Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:36Z
E = mc²
2ω² + 4ω + 5 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-φ²) dφ = √π / 2
94K
det| 2 1 ; 2 3 | = 4
\binom{n}{k} = \frac{n!}{k!(n-k)!}