Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 17:55Z
11x² + 3x + 4 = 0
det| 9 4 ; 1 10 | = 86
66K
ω = 2πf
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
174K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
d/dz [z^11] = 11z^10
335K
λ = h/p
\binom{n}{k} = \frac{n!}{k!(n-k)!}
119K