Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:41Z
E = mc²
\lim_{t\to 0} \frac{\sin t}{t} = 1
144K
2ω² + 4ω + 5 = 0
E = mc²
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 4 6 ; 4 5 | = -4
94K
det| 2 1 ; 2 3 | = 4
\frac{11}{6} \sum_{i=1}^{n} i^{2}
390K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
144K
2H₂ + O₂ → 2H₂O
F = G m₁m₂ / r²