Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:37Z
E = mc²
2ω² + 4ω + 5 = 0
det| 9 4 ; 1 10 | = 86
90K
∑_{k=1}^{n} k = n(n+1)/2
438K
E = mc²
det| 4 6 ; 0 5 | = 20
394K
CH₄ + 2O₂ → CO₂ + 2H₂O
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
94K
det| 2 1 ; 2 3 | = 4
det| 12 3 ; 4 13 | = 144
390K
det| 1 4 ; 2 2 | = -6
69K
∑_{k=1}^{n} k = n(n+1)/2
352K