Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-19 23:26Z
3θ² + 8θ + 7 = 0
∇ × E = −∂B/∂t
\frac{12}{3} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
61K
λ = h/p
\lim_{z\to 0} \frac{\sin z}{z} = 1
380K
iħ ∂ψ/∂t = Ĥψ
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
d/dβ [β^11] = 11β^10
PV = nRT
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}