Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:59Z
E = mc²
2ω² + 4ω + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
394K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
\oint_C \vec{F}\cdot d\vec{r} = 0
94K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
211K
det| 2 1 ; 2 3 | = 4
AgNO₃ + NaCl → AgCl↓ + NaNO₃
390K
\binom{n}{k} = \frac{n!}{k!(n-k)!}