Field Notes / Σ /sym/b26508
id=1 · host=uk.mattivster.me · 2026-10-18 20:07Z
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
144K
2ω² + 4ω + 5 = 0
E = mc²
CH₄ + 2O₂ → CO₂ + 2H₂O
394K
det| 10 7 ; 3 11 | = 89
29K
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 7 4 ; 4 8 | = 40
144K